Electric Fields

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    F q k.Ä•Q/d2 —Ä—

    47T%R2

Visualizing the Electric Fields

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Comparing Electrostatics & Gravity

  • Gravity only attracts

  • Electrostatics attract and repel

    Electrostatics Force: F kqga Field Strength: E = —C Field Strength: E = Electrostatic Constant: k 8.99\*109 Charge Units: Coulombs Gravity Force: Fg = Field Strength: g Field Strength: g = —r -6.67\*10-112$ Gravitational Constant: G — Mass Units: kilograms

Charge Densities

Useful idea: charge density Line of charge: charge per unit length X Sheet of charge: charge per unit area o Volume of charge: charge per unit volume — p p = Q/V

Practice Question 1

Find the electric field at the origin due to the three charges shown in the diagram. — o, -z.eo > 9 8 7 6 5 4 3 2 1 o É.m.r= < 0 a-Z.qwoY-7.95.1DY, O -7.ts•'0 10 6 78 9

Practice Question 2

Determine the x-coordinate where the electric field is zero using the diagram below. Cll.) z TOT - — 1 r:q.sc z. —l.qqw

Practice Question 3

A thin insulating semicircle of charge Q with radius R is centered around point C. Determine the electric field at point C due to the semicircle of charge. c

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Practice Question 4

计算机生成了可选文字: 卜 ， t P

  • Find the electric field a distance d from a long straight insulating rod of length L at point P perpendicular to the wire and eduidistant from each end of the wire if the wire is uniformly charged

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  • What if the line is infinitely

    long

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  • What is the E field if the distance d is

    infinite?
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Practice Question 4

Find the electric field at a point on the axis (perpendicular to the ring) of a thin insulating ring of radius R that is uniformly charged. g g- x RdO z

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Practice Question 5

Find the electric field due to a uniformly charged insulating disk of radius R at a point P perpendicular to the disk as shown in the diagram.

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Practice Question 6

Find the electric field due to a finite uniformly charged rod of length L lying on its side at some distance d away from the end of the rod. d

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